Tallon Griekspoor / Robin Haase - Vega Hernandez D / Vasilevski A


name
1
2
3
sets
Tallon Griekspoor / Robin Haase
Vega Hernandez D / Vasilevski A
4
6
6
4
10
7
2
1
Live Sports Streaming
5
Aces
8
3
Double Faults
3
25/28 (89%)
Second Serve
23/26 (88%)
31/59 (53%)
First Serve
35/61 (57%)
25/31 (81%)
First Serve Points
27/35 (77%)
18/28 (64%)
Second Serve Points
16/26 (62%)
18
Receiver points won
16
6
Max points in a row
7
61
Points won
59
1/1 (100%)
Break points
1/2 (50%)
Tallon Griekspoor / Robin Haase vs Vega Hernandez D / Vasilevski A Head 2 Head
Tallon Griekspoor / Robin Haase Matches
Griekspoor T / Haase R
versus
Drzewiecki K / Walkow S
3
6
77
62
10
12
04 Sep 20
Finished
Griekspoor T / Haase R
versus
Vega Hernandez D / Vasilevski A
4
6
6
4
10
7
03 Sep 20
Finished
Griekspoor T / Haase R
versus
Balaji N / Gabashvili T
6
4
6
0
02 Sep 20
Finished
Vega Hernandez D / Vasilevski A Matches
Griekspoor T / Haase R
versus
Vega Hernandez D / Vasilevski A
4
6
6
4
10
7
03 Sep 20
Finished
Verdugo H H / Van De Zandschulp B
versus
Vega Hernandez D / Vasilevski A
3
6
4
6
02 Sep 20
Finished

You can follow Tallon Griekspoor / Robin Haase - Vega Hernandez D / Vasilevski A live score and live stream here on Scoreaxis.com, along with full match statistics and video highlights (when available). Tallon Griekspoor / Robin Haase vs Vega Hernandez D / Vasilevski A live streaming options are also shown on this page. Tallon Griekspoor / Robin Haase vs Vega Hernandez D / Vasilevski A (2020 ATP Challenger Ostrava, Czech Republic Men Doubles) will kick off at 12:40 on 03 Sep 20.

The match will be played on clay courts in Ostrava, Czech Republic Men Double (Czech Republic).

Based purely on odds, the predicted winner of the match is Vega Hernandez D / Vasilevski A. Our predictions should not be used for betting or gambling on sports and scoreaxis.com accepts no responsibility or liability for any (direct or indirect) financial or other loss that may result from using our statistical data, predictions or any other content present on this website.